12x^2-104x+210=0

Solution for 12x^2-104x+210=0 equation:

12x^2-104x+210=0

a = 12; b = -104; c = +210;
Δ = b2-4ac
Δ = -1042-4·12·210
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-4\sqrt{46}}{2*12}=\frac{104-4\sqrt{46}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+4\sqrt{46}}{2*12}=\frac{104+4\sqrt{46}}{24}
$